https://oj.leetcode.com/problems/binary-tree-inorder-traversal/
Given a binary tree, return the inorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1 \ 2 / 3
return [1,3,2]
.
Note: Recursive solution is trivial, could you do it iteratively?
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> result;
vector<int> inorderTraversal(TreeNode *root) {
if( root != NULL ) {
inorderTraversal(root->left);
result.push_back(root->val);
inorderTraversal(root->right);
return result;
} else {
return result;
}
}
};
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